Comments on: Calculating Incident Solar Radiation on Inclined Surface (Easy Method) https://synergyfiles.com/2015/10/calculating-incident-solar-radiation-on-inclined-surface-easy-method/ Portal for Renewable Energy & Sustainability Sat, 25 Jan 2025 19:06:15 +0000 hourly 1 https://wordpress.org/?v=6.7.2 By: Ross https://synergyfiles.com/2015/10/calculating-incident-solar-radiation-on-inclined-surface-easy-method/#comment-129046 Wed, 01 Jun 2022 07:56:01 +0000 http://synergyfiles.com/?p=637#comment-129046 In reply to Ernest.

it looks like beta is the angle of the solar cell to the horizontal (referring to the diagram in the article)

]]> By: Ernest https://synergyfiles.com/2015/10/calculating-incident-solar-radiation-on-inclined-surface-easy-method/#comment-9165 Sat, 21 Apr 2018 23:07:12 +0000 http://synergyfiles.com/?p=637#comment-9165 G (inclined) = G(horizontal) * Sin (α+β) / Sinα

What does β stands for in this formular?

]]> By: Haroon https://synergyfiles.com/2015/10/calculating-incident-solar-radiation-on-inclined-surface-easy-method/#comment-2340 Thu, 07 Apr 2016 11:11:48 +0000 http://synergyfiles.com/?p=637#comment-2340 In reply to Ankit Kumar.

It is just an adjustment factor. This is because Declination is not Zero on January 1 (1st day of the year) . It is 0 on March 22 and September 22

]]> By: Ankit Kumar https://synergyfiles.com/2015/10/calculating-incident-solar-radiation-on-inclined-surface-easy-method/#comment-2338 Thu, 07 Apr 2016 10:09:30 +0000 http://synergyfiles.com/?p=637#comment-2338 δ= 23.45° * Sin[ 360/365 (284+d)]

Please let me know where does the constant 284 come from in the above equation.

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